[8.5.] “Quantifier Negation (QN).” (Ch.9:6)
This is fifth and final rule for dealing with quantifiers. Because it is an equivalence rule it can be applied to parts of a line. It has four forms:
1. (x)(. . . x . . .) :: ~($x)~(. . . x . . .)
This form allows you to replace a universal quantifier with an existential quantifier embedded between two tildes (and vice versa), e.g.,
1. (x)(Fx É Gx) p 1. ~($x)~(Fx É Gx) p
2. ~($x)~(Fx É Gx) 1 QN 2. (x)(Fx É Gx) 1 QN
In English: the fact that every x that is F is also G implies that it is false that there is an x such that it is false that if that x is an F, then it’s a G (and vice versa).
2. ($x)(. . . x . . .) :: ~(x)~(. . . x . . .)
This form allows you to replace an existential quantifier with a universal quantifier embedded between two tildes (and vice versa), e.g.,
1. ($x)(Fx · Gx) p 1. ~(x)~(Fx · Gx) p
2. ~(x)~(Fx · Gx) 1 QN 2. ($x)(Fx · Gx) 1 QN
In English: the fact that there is an x that is both F and G implies that it is false that, for all x, it is not the case that x is both F and G (and vice versa).
3. (x)~(. . . x . . .) :: ~($x)(. . . x . . .)
This form allows you to move a tilde that immediately follows a universal quantifier to the front of that quantifier, thereby changing it from universal to existential (and vice versa); e.g.
1. (x)~(Fx · Gx) p 1. ~($x)(Fx · Gx) p
2. ~($x)(Fx · Gx) 1 QN 2. (x)~(Fx · Gx) p
In English: the fact that for all x, it is false that x is both F and G implies that there is no such thing as an x that is both F and G (and vice versa).
4. ($x)~(. . . x . . .) :: ~(x)(. . . x . . .)
This form allows you to move a tilde that immediately follows an existential quantifier to the front of that quantifier, thereby changing it from existential to universal (and vice versa); e.g.
1. ($x)~(Fx · Gx) p 1. ~(x)(Fx · Gx) p
2. ~(x)(Fx · Gx) 1 QN 2. ($x)~(Fx · Gx) 1 QN
In English: the fact that there is an x that is not both F and G implies that it is false that all x’s are F and G (and vice versa).
[8.5.1.] Identifying Incorrect Uses of QN.
We will go through exercise 9-4 (pp.215-216) in class: this exercise asks you to identify incorrect uses of QN and to give a premise which could be validly inferred using that rule.
Answers to ex. 9-4:
1. incorrect; ~($x)Fx
2. correct
3. incorrect; ~($x)(~Fx Ú Gx)
4. incorrect; (y)(Ry · ~Ky)
5. incorrect; (y)~(~Ry · Ky)
6. correct
7. correct
8. correct -- notice the typos in textbook; the argument should read:
(8) 1. (y)~[(Fy) É ($z)(Gz · Hz)]
2. ~($y)[Fy É ($z)(Gz · Hz)]
9. incorrect; ~($y)Fy É ($z)(Gz · Hz) -- notice the typos in textbook; the argument should read:
(9) 1. (y)~Fy É ($z)(Gz· Hz)
2. ~($y)~Fy É ($z)(Gz · Hz)
10. incorrect; ~($x)(Fx É Gx)
[8.5.2.] Proofs Using QN.
Here’s a proof that contains multiple uses of QN:
1. ~(x)[Ax Ú Bx] p
2. ~($x)~(Cx É Ax) p
3. ($x)~Cx É ($y)~Fy p /\~(y)Fy
4. ($x)~[Ax Ú Bx] 1 QN
5. (x)(Cx É Ax) 2 QN
6. ~(Ax Ú Bx) 4 EI
7. Cx É Ax 5 UI
8. ~Ax · ~Bx 6 DeM
9. ~Ax 8 Simp
10. ~Cx 7, 9 MT
11. ($x)~Cx 10 EG
12. ($y)~Fy 3, 11 MP
13. ~(y)Fy 12 QN
Exercise 9-5 (p.221)
· do #1-15 (omit 16-20, unless you’re up for a real challenge)
Stopping point for Monday March 31. For next time, complete ex.9-5. No new reading. We will go through all of 9-5 on Wednesday, and Friday we will review for your third test, which is one week from today.
This page last updated 3/31/2008.
Copyright © 2008 Robert Lane. All rights reserved.